Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set: 49

Answer

$x = \frac{1}{3}$ or $x =-0.5$

Work Step by Step

$12x^2 + 2x - 2 = 0$ Step 1: is not needed because there is no fractions. $12x^2 + 2x - 2 = 0$ Step 2: is not needed $12x^2 + 2x - 2 = 0$ Step 3: is not needed since no simplifying can be done on either side of the equation. $12x^2 + 2x - 2 = 0$ Step 4: The equation is quadratic. Step 5: Rewrite the equation in standard form. $12x^2 + 2x-2 = 0$ Step 6: Factor. $(6x -2)(2x +1) = 0$ Step 7: Set each factor equal to 0. $6x -2 = 0$ or $2x +1 = 0$ Solve each equation. $6x = +2$ or $2x =-1$ $x = \frac{1}{3}$ or $x =-0.5$
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