Answer
$x = +0.2$ or $x =+4$
Work Step by Step
$\frac{5x^2}{6} - \frac{7x}{2} + \frac{2}{3} = 0$
Step 1:
Clear the equation from fractions.
$6(\frac{5x^2}{6} - \frac{7x}{2} + \frac{2}{3} )= 6\times0$
Step 2: Use the distribute property.
$5x^2 - 21x + 4 = 0$
Step 3:
is not needed since no simplifying can be done on either side of the equation.
$5x^2 - 21x + 4 = 0$
Step 4:
The equation is quadratic.
Step 5: Rewrite the equation in standard form.
$5x^2 -21x+ 4 = 0$
Step 6: Factor.
$(5x -1)(x -4) = 0$
Step 7: Set each factor equal to 0.
$5x -1 = 0$ or $x -4 = 0$
Solve each equation.
$5x = +1$ or $x =+4$
$x = +0.2$ or $x =+4$
