Answer
$x = +0.4$ or $x =-0.5$
Work Step by Step
$\frac{x^2}{2} + \frac{x}{20} = \frac{1}{10}$
Step 1:
Clear the equation from fractions.
$20(\frac{x^2}{2} + \frac{x}{20}) = 20 \times \frac{1}{10}$
Step 2: Use the distribute property.
$10x^2 + x = 2$
Step 3:
is not needed since no simplifying can be done on either side of the equation.
$10x^2 + x = 2$
Step 4:
The equation is quadratic.
$10x^2 + x = 2$
Step 5: Rewrite the equation in standard form.
$10x^2 + 1x-2 = 0$
Step 6: Factor.
$(5x-2)(2x +1) = 0$
Step 7: Set each factor equal to 0.
$5x -2 = 0$ or $2x +1 = 0$
Solve each equation.
$5x = +2$ or $2x =-1$
$x = +0.4$ or $x =-0.5$