Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set: 35

Answer

$y = 8$

Work Step by Step

$2y + 5(y - 4) = 4y - 2(y - 10)$ Step 1: is not need because there is no fractions. Step 2: Use the distribute property. $2y + 5y - 20 = 4y - 2y + 20$ Step 3: simplify each side of the equation by combining like terms. $7y - 20 = 2y + 20$ Step 4: The equation is linear. Step 5: Get all variable terms on one side and all numbers on the other side by using the addition property of equality. $7y - 20 + 20 = 2y + 20 + 20$ $7y = 2y + 40$ $7y - 2y = 2y + 40 - 2y$ $5y = 40$ Step 6: Get the variable alone by using the multiplication property of equality. $5y \times \frac{1}{5} = 40 \times \frac{1}{5} $ $y = 8$ Final Step: Check each solution in the original equation. $2\times8 + 5( 8 -4) = 4 \times 8 - 2 (8 - 10)$ $16 + 20 = 32 +4$ $36 = 36$
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