Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set: 34

Answer

$c = +1$ or $c =+4$

Work Step by Step

$\frac{c^2}{20} - \frac{c}{4} + \frac{1}{5} = 0$ Step 1: Clear the equation from fractions. $20(\frac{c^2}{20} - \frac{c}{4} + \frac{1}{5}) = 20\times0$ Step 2: Use the distribute property. $c^2- 5c + 4 = 0$ Step 3: is not needed since no simplifying can be done on either side of the equation. Step 4: The equation is quadratic. $c^2- 5c + 4 = 0$ Step 5: Rewrite the equation in standard form. $c^2 -5c+ 4 = 0$ Step 6: Factor. $(c -1)(c -4) = 0$ Step 7: Set each factor equal to 0. $c -1 = 0$ or $c -4 = 0$ Solve each equation. $c = +1$ or $c =+4$
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