Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set: 27

Answer

n=1

Work Step by Step

$\frac{n-3}{4} + \frac{n+5}{7} = \frac{5}{14} \lt=\gt \frac{7n-21}{28} + \frac{4n+20}{28} = \frac{5}{14} \lt=\gt \frac{11n-1}{28} = \frac{10}{28} \lt=\gt 11n-1 = 10 \lt=\gt n=1$
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