Answer
$(3x-4y)(9x^{2}+12xy+16y^{2})$
Work Step by Step
Step 1: $27x^{3}-64y^{3}$
Step 2: $(3x)^{3}-(4y)^{3}$
Step 3: $(3x-4y)((3x)^{2}+(3x)(4y)+(4y)^{2})$
Step 4: $(3x-4y)(9x^{2}+12xy+16y^{2})$
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