Answer
Appendix A - Ex. Set : 37 (Answer)
$(4x + \frac{1}{3})(4x - \frac{1}{2})$
$= 16x^2 - \frac{2x}{3} - \frac{1}{6}$
Work Step by Step
Appendix A - Ex. Set : 37 (Solution)
$(4x + \frac{1}{3})(4x - \frac{1}{2})$
$= (4x)(4x) + (4x) (-\frac{1}{2}) + (\frac{1}{3})(4x) + (\frac{1}{3})(-\frac{1}{2})$ (FOIL p. 383)
$= 16x^2 - 2x + \frac{4x}{3} - \frac{1}{6}$
$= 16x^2 - \frac{2x}{3} - \frac{1}{6}$ (Combine like terms)