Answer
Appendix A - Ex. Set : 17 (Answer)
$(\frac{2a^{-2}b^5}{4a^2b^7})^{-2}$
$= 4a^8b^4$
Work Step by Step
Appendix A - Ex. Set : 17 (Solution)
$(\frac{2a^{-2}b^5}{4a^2b^7})^{-2}$
$= \frac{(2a^{-2}b^5)^{-2}}{(4a^2b^7)^{-2}}$ (Power of a quotient)
$= \frac{2^{-2}a^4b^{-10}}{(2^2)^{-2}a^{-4}b^{-14}}$ (Power rule)
$= 2^{-2-(-4)}a^{4-(-4)}b^{-10-(-14)}$ (Quotient rule)
$= 2^2a^8b^4$
$= 4a^8b^4$
