Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix A - Exercise Set: 16

Answer

$\frac{27}{a^{12}b^{21}}$

Work Step by Step

$(\frac{3a^{-4}}{b^{7}})^{3}$ =$(\frac{3}{a^{4}b^{7}})^{3}$ =$(\frac{3^{3}}{(a^{4})^{3}(b^{7})^{3}})$ =$\frac{27}{a^{12}b^{21}}$
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