Answer
$\frac{27}{a^{12}b^{21}}$
Work Step by Step
$(\frac{3a^{-4}}{b^{7}})^{3}$
=$(\frac{3}{a^{4}b^{7}})^{3}$
=$(\frac{3^{3}}{(a^{4})^{3}(b^{7})^{3}})$
=$\frac{27}{a^{12}b^{21}}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Appendix A - Exercise Set - Page 975: 16
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