Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix A - Exercise Set - Page 975: 10

Answer

$ \frac{15}{16}$

Work Step by Step

$1^{-3} - 4^{-2} = \frac{1}{1^3} - \frac{1}{4^2} = 1 - \frac{1}{16} = \frac{15}{16}$
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