Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Skills Handbook - Scientific Notation and Significant Digits - Exercises - Page 980: 11

Answer

$$6.4\times 10^{5}$$

Work Step by Step

The number of digits in the number between $1$ and $10$ are the number of significant digits: $1.6\times 10^{2}$ has $2$ significant digits $4.0\times 10^{3}$ also has $2$ significant digits. Multiply and rearrange factors: $$(1.6\times 10^{2})(4.0\times 10^{3})=(1.6\times 4.0)\times (10^{2}\times 10^{3})=6.4\times 10^{5}.$$
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