Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

End-of-Course Assessment: 2

Answer

G. $r=\sqrt {\frac{Gm_{1}m_{2}}{F}}$

Work Step by Step

Multiply both sides of the equation by $r^{2}$. This cancels out $r^{2}$ on the right side of the equation. $r^{2}{\times}F={\frac{Gm_{1}m_{2}}{r^{2}}}{\times}r^{2}$ $r^{2}{\times}F={Gm_{1}m_{2}}$ Divide both sides of the equation by F. This cancels out F out on the left side of the equation. $\frac{r^{2}{\times}F}{F}=\frac{{Gm_{1}m_{2}}}{F}$ $r^{2}=\frac{{Gm_{1}m_{2}}}{F}$ Take the square root of both sides of the equation. The power on r and the square root cancel one another out. $\sqrt {r^{2}}=\sqrt {\frac{{Gm_{1}m_{2}}}{F}}$ $r=\sqrt {\frac{{Gm_{1}m_{2}}}{F}}$
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