Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Get Ready! - Page 357: 9

Answer

$49a^2-100$

Work Step by Step

Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the given expression, $ (7a+10)(7a-10) ,$ is equivalent \begin{align*} & (7a)^2-(10)^2 \\&= 49a^2-100 .\end{align*} Hence, the product of the given expression is $ 49a^2-100 $.
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