Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Get Ready! - Page 357: 8

Answer

$3y^2-14y+8$

Work Step by Step

Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression, $ (3y-2)(y-4) ,$ is equivalent to \begin{align*} & 3y(y)+3y(-4)-2(y)-2(-4) \\&= 3y^2-12y-2y+8 \\&= 3y^2-14y+8 .\end{align*} Hence, the product is $ 3y^2-14y+8 $.
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