Answer
$3y^2-14y+8$
Work Step by Step
Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression, $
(3y-2)(y-4)
,$ is equivalent to
\begin{align*}
&
3y(y)+3y(-4)-2(y)-2(-4)
\\&=
3y^2-12y-2y+8
\\&=
3y^2-14y+8
.\end{align*}
Hence, the product is $
3y^2-14y+8
$.