Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 31

Answer

$40|xy|\sqrt{3}$

Work Step by Step

RECALL: $\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}, a\gt0, b\gt 0.$ Use the rule above to have $20\sqrt{(2x)(6xy^2)} \\=20\sqrt{12x^2y^2} \\=20\sqrt{4x^2y^2(3)} \\=20\sqrt{(2xy)^2(3)} \\=20(2)|xy|\sqrt{3} \\=40|xy|\sqrt{3}.$
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