Answer
$8|y^3|\sqrt{5y}$
Work Step by Step
RECALL:
$\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}, a\gt0, b\gt 0.$
Use the rule above to have
$\sqrt{(8y^5)(40y^2)}
\\=\sqrt{64y^6(5y)}
\\=\sqrt{(8y^3)^2(5y)}
\\=8|y^3|\sqrt{5y}.$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 29
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