Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 371: 10

Answer

$16$

Work Step by Step

Recall the property (pg. 367): $\sqrt[n]{a}\cdot \sqrt[n]{b}=\sqrt[n]{ab}$ (if $\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers) Applying this property, the given expression simplifies to: $=\sqrt{8\cdot32}$ $=\sqrt{256}$ $=\sqrt{16^2}$ $=16$
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