Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-4 Factoring Quadratic Expressions - Practice and Problem-Solving Exercises - Page 222: 83

Answer

$(0.5t+0.4)(0.5t-0.4)$

Work Step by Step

Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the given expression, $ 0.25t^2-0.16 ,$ is equivalent to \begin{align*} & (0.5t)^2-(0.4)^2 \\&= (0.5t+0.4)(0.5t-0.4) .\end{align*}
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