Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-4 Factoring Quadratic Expressions - Practice and Problem-Solving Exercises - Page 222: 63

Answer

$3(y+3)(y+5)$

Work Step by Step

Factoring the $GCF= 3 ,$ the given expression, $ 3y^2+24y+45 ,$ is equivalent to \begin{align*} 3(y^2+8y+15) .\end{align*} Using the factoring of trinomials in the form $x^2+bx+c,$ the expression above has $c= 15 $ and $b= 8 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ 3,5 \right\}.$ Using these two numbers, the factored form of the expression above is \begin{align*} 3(y+3)(y+5) .\end{align*}
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