Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-4 Factoring Quadratic Expressions - Practice and Problem-Solving Exercises - Page 222: 59

Answer

$2(3z+2)(3z-2)$

Work Step by Step

Factoring the $GCF= 2 ,$ the given $\text{ expression, }$ $ 18z^2-8 ,$ is equivalent to \begin{align*} 2(9z^2-4) \end{align*} Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the $\text{ expression }$ above is equivalent to \begin{align*} & 2[(3z)^2-(2)^2] \\&= 2[(3z+2)(3z-2)] \\&= 2(3z+2)(3z-2) \end{align*}
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