Answer
$-7\frac{1}{2}$
Work Step by Step
We substitute the values in. We have $\frac{3}{5}d+\frac{1}{10}h-\frac{7}{10}d-\frac{4}{5}h=\frac{3}{5}(5)+\frac{1}{10}(10)-\frac{7}{10}(5)-\frac{4}{5}(10)=3+1-\frac{7}{2}-8=4-\frac{7}{2}-8=4-3\frac{1}{2}-8=\frac{1}{2}-8=-7\frac{1}{2}$