Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-3 Linear Functions and Slope-Intercept Form - Practice and Problem-Solving Exercises - Page 79: 61

Answer

$m=\dfrac{15}{2}$

Work Step by Step

With the given points, $\left( 0, -\dfrac{1}{2} \right)$ and $\left( \dfrac{7}{5}, 10 \right)$, then \begin{array}{l}\require{cancel} y_1= -\dfrac{1}{2} ,\\y_2= 10 ,\\x_1= 0 ,\text{ and }\\ x_2= \dfrac{7}{5} .\end{array} Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is \begin{array}{l}\require{cancel} m=\dfrac{-\dfrac{1}{2}-10}{0-\dfrac{7}{5}} \\\\ m=\dfrac{-\dfrac{1}{2}-\dfrac{20}{2}}{0-\dfrac{7}{5}} \\\\ m=\dfrac{-\dfrac{21}{2}}{-\dfrac{7}{5}} \\\\ m=\dfrac{\dfrac{21}{2}}{\dfrac{7}{5}} \\\\ m=\dfrac{21}{2}\div\dfrac{7}{5} \\\\ m=\dfrac{21}{2}\cdot\dfrac{5}{7} \\\\ m=\dfrac{\cancel{21}^3}{2}\cdot\dfrac{5}{\cancel7^1} \\\\ m=\dfrac{3}{2}\cdot\dfrac{5}{1} \\\\ m=\dfrac{15}{2} .\end{array} Hence, the slope is $ m=\dfrac{15}{2} $.
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