Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-3 Linear Functions and Slope-Intercept Form - Practice and Problem-Solving Exercises - Page 79: 60

Answer

$m=\dfrac{7}{5}$

Work Step by Step

With the given points, $\left( -\dfrac{1}{2}, -\dfrac{1}{2} \right)$ and $\left( -3,-4 \right)$, then \begin{array}{l}\require{cancel} y_1= -\dfrac{1}{2} ,\\y_2= -4 ,\\x_1= -\dfrac{1}{2} ,\text{ and }\\ x_2= -3 .\end{array} Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is \begin{array}{l}\require{cancel} m=\dfrac{-\dfrac{1}{2}-(-4)}{-\dfrac{1}{2}-(-3)} \\\\ m=\dfrac{-\dfrac{1}{2}+4}{-\dfrac{1}{2}+3} \\\\ m=\dfrac{-\dfrac{1}{2}+\dfrac{8}{2}}{-\dfrac{1}{2}+\dfrac{6}{2}} \\\\ m=\dfrac{\dfrac{7}{2}}{\dfrac{5}{2}} \\\\ m=\dfrac{\dfrac{7}{\cancel2}}{\dfrac{5}{\cancel2}} \\\\ m=\dfrac{7}{5} .\end{array} Hence, the slope is $ m=\dfrac{7}{5} $.
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