Answer
\begin{array}{l}\require{cancel}
\text{Slope-Intercept Form: }
y=-\dfrac{4}{3}x+\dfrac{5}{6}
\\\text{Slope: }
-\dfrac{4}{3}
\\\text{$y$-intercept: }
\left(0, \dfrac{5}{6}\right)
\end{array}
Work Step by Step
Using the properties of equality, the given equation, $
8x+6y=5
,$ is equivalent to
\begin{array}{l}\require{cancel}
6y=-8x+5
\\\\
\dfrac{6y}{6}=\dfrac{-8x+5}{6}
\\\\
y=-\dfrac{8}{6}x+\dfrac{5}{6}
\\\\
y=-\dfrac{4}{3}x+\dfrac{5}{6}
.\end{array}
Using $y=mx+b$ (where $m$ is the slope and $b$ is the $y$-intercept) or the Slope-Intercept Form of linear equations, then the equation above has the following properties
\begin{array}{l}\require{cancel}
\text{Slope-Intercept Form: }
y=-\dfrac{4}{3}x+\dfrac{5}{6}
\\\text{Slope: }
-\dfrac{4}{3}
\\\text{$y$-intercept: }
\left(0, \dfrac{5}{6}\right)
.\end{array}