Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-3 Linear Functions and Slope-Intercept Form - Practice and Problem-Solving Exercises - Page 78: 18

Answer

$y=-\dfrac{1}{3}x-2$

Work Step by Step

The given graph has a $y$-intercept of $-2$ and passes through the points $(0,-2)$ and $(-6,0).$ With the given points, \begin{align*} y_1&= -2 ,\\y_2&= 0 ,\\x_1&= 0 ,\text{ and }\\ x_2&= -6 .\end{align*} Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is \begin{align*} m&=\dfrac{-2-0}{0-(-6)} \\\\&= \dfrac{-2-0}{0+6} \\\\&= \dfrac{-2}{6} \\\\&= -\dfrac{1}{3} .\end{align*} With a slope of $-\dfrac{1}{3}$ and a $y$-intercept of $-2$, by the Slope-Intercept Form of linear equations ($y=mx+b$), then the equation of the line is \begin{align*} y=-\dfrac{1}{3}x-2 .\end{align*}
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