Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 13 - Periodic Functions and Trigonometry - Get Ready!: 9

Answer

$$\frac{15}{7}$$

Work Step by Step

Dividing by a fraction is equivalent to multiplying by the reciprocal of the fraction. $$\frac{3-\frac{1}{2}}{\frac{7}{6}}=\bigg(3-\frac{1}{2}\bigg)\times \frac{6}{7}$$ Next convert the whole number $3$ to a fraction with a common denominator in order to subtract the fractions: $$=\bigg(\frac{6}{2}-\frac{1}{2}\bigg)\times \frac{6}{7}=\frac{5}{2}\times \frac{6}{7}=\frac{5}{2}\times \frac{3\times 2}{7}.$$ Cancel common factors: $$=\frac{5}{1}\times \frac{3}{7}=\frac{15}{7}.$$
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