Answer
All three vectors have the same magnitude.
The magnitude of a vector $\vec{v}=\langle v_x,v_y\rangle$ is $|\vec{v}|=\sqrt{v_x^2+v_y^2}.$
Therefore,
$$|\langle 3,4\rangle|=\sqrt{3^2+4^2}=5$$
$$|\langle -4,3\rangle|=\sqrt{(-4)^2+3^2}=5$$
$$|\langle 4,-3\rangle|=\sqrt{4^2+(-3)^2}=5.$$
Work Step by Step
The magnitude of a vector $\vec{v}=\langle v_x,v_y\rangle$ is $|\vec{v}|=\sqrt{v_x^2+v_y^2}.$
Therefore,
$$|\langle 3,4\rangle|=\sqrt{3^2+4^2}=5$$
$$|\langle -4,3\rangle|=\sqrt{(-4)^2+3^2}=5$$
$$|\langle 4,-3\rangle|=\sqrt{4^2+(-3)^2}=5.$$
