Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Lesson Check - Page 678: 2

Answer

$_9P_4=3,024$

Work Step by Step

Using $_nP_r=\dfrac{n!}{(n-r)!},$ then the value of the given expression, $ _9P_4 ,$ is \begin{align*}\require{cancel} & \dfrac{9!}{(9-4)!} \\\\&= \dfrac{9!}{5!} \\\\&= \dfrac{9(8)(7)(6)(5!)}{5!} \\\\&= \dfrac{9(8)(7)(6)(\cancel{5!})}{\cancel{5!}} \\\\&= 9(8)(7)(6) \\&= 3024 .\end{align*} Hence, $ _9P_4=3,024 .$
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