Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-4 Solving Equations - Lesson Check: 6

Answer

$k=-\frac{1}{6}h-\frac{7}{3}$

Work Step by Step

We start by adding 2k to both sides. That gives us $6k+h=-14$. Now, we subtract h from both sides to isolate k with its coefficient, which gives us $6k=-h-14$. Finally, we divide both sides by 6 to fully isolate k. $\frac{6k}{6}=\frac{-h-14}{6}$ equals $k=-\frac{1}{6}h-\frac{7}{3}$
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