Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-3 Algebraic Expressions - Practice and Problem-Solving Exercises - Page 24: 72

Answer

$–p – \frac{2q}{3}$

Work Step by Step

First, we make the last term have the common denominator of $3$: = $–\frac{p}{3} –\frac{2p}{3} + \frac{q}{3} – \frac{3q}{3}$ Now we combine like terms and put the fractions in simplest form: =$–\frac{3p}{3} – \frac{2q}{3}$ =$–p – \frac{2q}{3}$
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