Answer
95.722
Work Step by Step
Result from example 5:
$f(n) = 7f(n/2)+15n^2/4$
and $f(1)=1$
We have been given $32 \times 32$ matrices. Therefore in this case $n=32$
Then
$f(32) = 7f(16)+15\frac{32^2}{4}$
$= 7f(16)+3840$
$ = 7(7f(8)+15\frac{16^2}{4})+3840$
$= 7(7f(8)+960)+3840$
$= 7(7[7f(4)+15\frac{8^2}{4}]+960)+3840$
$= 7(7[7f(4)+240]+960)+3840$
$= 7(7[7(7f(2)+15\frac{4^2}{4}]+240]+960)+3840$
$= 7(7[7(7f(2)+60]+240]+960)+3840$
$= 7(7[7(7[7f(1)+15\frac{2^2}{4}]+60)+240]+960)+3840$
$= 7(7[7(7[7f(1)+15]+60)+240]+960)+3840$
$= 7(7[7(7\times22+60)+240]+960)+3840$
$= 7(7\times1738+960)+3840$
$=7\times13.126+3840$
$=95.722$
