Answer
5.315$\times 10^{-5}$
Work Step by Step
The number of ways to select 5 correct numbers out of 6 = C(6,5) = 6
Number of ways to select 1 number out of the remaining 34 = C(34,1) =34
Total possibilities = C(40,6) = 3838380
probablity = $\frac{C(6,5)\times C(34,1)}{C(40,6) }$ =$\frac{6\times 34}{3838380}$
= 5.315$\times 10^{-5}$
