Answer
1 9 36 84 126 126 84 36 9 1
Work Step by Step
The row of $(_k^9)$ is the binomial coefficients evaluated at k = 1,2,3,4,5,6,7,8, and 9. Thus:
$(_0^9) = \frac{9!}{0!(9-0)!}$ = 1
$(_1^9) = \frac{9!}{1!(9-1)!}$ = 9
$(_2^9) = \frac{9!}{2!(9-2)!}$ = 36
$(_3^9) = \frac{9!}{3!(9-3)!}$ = 84
$(_4^9) = \frac{9!}{4!(9-4)!}$ = 126
$(_5^9) = \frac{9!}{5!(9-5)!}$ = 126
$(_6^9) = \frac{9!}{6!(9-6)!}$ = 84
$(_7^9) = \frac{9!}{7!(9-7)!}$ = 36
$(_8^9) = \frac{9!}{8!(9-8)!}$ = 9
$(_9^9) = \frac{9!}{9!(9-9)!}$ = 1
