Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.3 - Permutations and Combinations - Exercises - Page 413: 5

Answer

(a) 120 (b) 720 (c) 8 (d) 6720 (e) 40320 (f) 3628800

Work Step by Step

We apply the formula $P(n, r)=\frac{n!}{(n-r)!}$ to find (a) $P(6, 3)=\frac{6!}{(6-3)!}=\frac{6!}{3!}=120$ (b) $P(6, 5)=\frac{6!}{(6-5)!}=\frac{6!}{1!}=720$ (c) $P(8, 1)=\frac{8!}{(8-1)!}=\frac{8!}{7!}=8$ (d) $P(8, 5)=\frac{8!}{(8-5)!}=\frac{8!}{3!}=6720$ (e) $P(8, 8)=\frac{8!}{(8-8)!}=\frac{8!}{0!}=40320$ (f) $P(10, 9)=\frac{10!}{(10-9)!}=\frac{10!}{1!}=3628800$
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