Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.3 - Permutations and Combinations - Exercises - Page 413: 3

Answer

720

Work Step by Step

The number of permutations of {a, b, c, d, e, f, g} which end with 'a' are same as the number of permutations of {b, c, d, e, f, g} because we can append an 'a' at the end of each of its permutations to get the desired permutation. Therefore, The number of permutations of {a, b, c, d, e, f, g} which end with 'a' = the number of permutations of {b, c, d, e, f, g} = $6\times5\times4\times3\times2\times1$ or 6! = 720
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