Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.3 - Permutations and Combinations - Exercises - Page 413: 16

Answer

512 subsets with odd number of elements.

Work Step by Step

If the set has 10 elements , then the number of subsets with $k$-elements is given by $C$(10,$k$) In our case we take $k$ = 1,3,5,7,9 Number of subsets = $C$(10,1)+$C$(10,3)+$C$(10,5)+$C$(10,7)+$C$(10,9) = 20 + 120 + 252 + 120 + 20 = 512
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