Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.1 - The Basics of Counting - Exercises - Page 398: 61

Answer

$16^{10} + 16^{26} + 16^{58}$

Work Step by Step

There are 16 hexadecimal digits. Therefore, for each place we have 16 choices. For 10 Hexadecimal digits we have $16^{10}$ choices. For 26 Hexadecimal digits we have $16^{26}$ choices. For 58 Hexadecimal digits we have $16^{58}$ choices. Applying sum rule we get, $16^{10} + 16^{26} + 16^{58}$ choices.
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