Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.1 - The Basics of Counting - Exercises - Page 398: 54

Answer

8268650 different initials

Work Step by Step

Number of 2 different initials = 26$\times$25 = 650 Number of 3 different initials = 26$\times$25$\times$24 = 15600 Number of 4 different initials = 26$\times$25$\times$24$\times$23 = 358800 Number of 5 different initials = 26$\times$25$\times$24$\times$23$\times$22 = 7893600 Total number of initials = 7893600 +358800 +15600 + 650 = 8268650
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.