Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.1 - The Basics of Counting - Exercises - Page 397: 31

Answer

20,077,200.

Work Step by Step

Step 1- Find the number of ways to choose the letters. By the sum -rule this is the sum of the number of ways to use two letters and the number of ways to use three letters. By the product rule there are ${26^2}$ ways to choose two letters and $26^3$ ways to choose three letters. Therefore there are $26^2$ + $26^3$ ways to choose the letters. Step 2-Similarly there are $10^2$ + $10^3$ ways to choose the digits. (10 ways to choose a digit -0,1,...,9) Thus the answer to the question is ($26^2 + 26^3 )(10^2 + 10^3$) = 18252 · 1100 = 20,077,200.
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