Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.1 - The Basics of Counting - Exercises - Page 396: 3

Answer

a) $4^{10}$ b) $5^{10}$

Work Step by Step

a) When the student has to attempt every question he has 4 choices for each question which are independent of each other . So total ways becomes 4$\times$4.... (10 times) = $4^{10}$. b) When the student can skip a question he has 5(4 + not attempting) choices for each question which are independent of each other . So total ways becomes 5$\times$5.... (10 times) = $5^{10}$.
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