Answer
--Using structural induction to show that n(T ) ≥ 2h(T ) + 1, where T is a full binary tree, n(T ) equals the number of vertices of T , and h(T ) is the height of T .
Work Step by Step
--procedure A(m, n: nonnegative integers)
-if m = 0 then return 2n
-else if n = 0 then return 0
-else if n = 1 then return 2
-else return A(m − 1, A(m, n − 1))