Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 4 - Section 4.6 - Cryptography - Exercises - Page 304: 1

Answer

a) GR QRW SDVV JR. b) QB ABG CNFF TB. c) QX UXM AHJJ ZX.

Work Step by Step

a) We need to replace each letter by the letter three places later in the alphabet. Thus D becomes G, 0 becomes R, and so on. The resulting message is GR QRW SDVV JR. b) We need to replace each letter by the letter 13 places later in the alphabet. Thus D becomes Q, 0 becomes B (we cycle, with A following Z), and so on. The resulting message is QB ABG CNFF TB. c) This one is a little harder, so it is probably easiest to work with the numbers. For D we have p = 3 because D is the fourth letter of the alphabet. Then 3 · 3 + 7 mod 26 = 16, so the encrypted letter is the 17th letter, or Q (remember that we start the sequence at 0). Our original message has the following numerical values: 3-14 13-14-19 15-0-18-18 6-14. Multiplying each of these numbers by 3, adding 7, and reducing modulo 26 gives us 16-23 20-23-12 0-7-9-9 25-23. Translating back into letters we have QX UXM AHJJ ZX.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.