Answer
If $a|b$, then $a|bc$ for all integers $c$.
Work Step by Step
Let $a, b$ be integers s.t. $a|b$, where $a$ is nonzero. Now, consider the fixed but arbitrary integer $c$. $bc$ is also an integer. Because $a$ is a multiplicative factor of $b$, it is also a multiplicative factor of $bc$. Thus, the statement is correct.
