Answer
Answer is 6, 17, 49, 143, 421
Work Step by Step
first of all, we have an = 2^n + 5 ⋅ 3^n for n = 0, 1, 2, … .
a0=2^0+5.3^0 =1+5=6
a1=2^1+5.3^1 =2+15=17
a2=2^2+5.3^2 =4+45=47
a3=2^3+5.3^3 =8+135=143
a4=2^4+5.3^4 =16+405=421
Discrete Mathematics and Its Applications, Seventh Edition
by Rosen, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0073383090
ISBN 13:
978-0-07338-309-5
Chapter 2 - Section 2.4 - Sequences and Summations - Exercises - Page 168: 11
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