Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.4 - Sequences and Summations - Exercises - Page 167: 4

Answer

a) 1,-2,4,-8 b) 3,3,3,3 c) 8,11,23,71 d) 2,0,8,0

Work Step by Step

a) Given: $(-2)^n$ Here, $a_0=(-2)^0=1; a_1=(-2)^1=-2;a_2=(-2)^2=4;a_3=(-2)^3=-8$ b) Since, the constant expression contains no $n$ variable, then we have $a_0=3; a_1=3;a_2=3;a_3=3$ c) Given: $7+4^n$ $a_0=7+4^0=8; a_1=7+4^1=11;a_2=7+4^2=23;a_3=7+4^3=71$ d) Given: $2^n+(-2)^n$ Here, we have $a_0=2^0+(-2)^0=2; a_1=2^1+(-2)^1=0;a_2=2^2+(-2)^2=8;a_3=2^3+(-2)^3=0$
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