Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.1 - Sets - Exercises - Page 126: 34

Answer

a) $A^3=\{(a,a,a)\}$ b) $A^3=\{(0,0,0), (0,0,a), (0,a,0), (0,a,a), (a,0,0), (a,0,a), (a,a,0), (a,a,a)\}$

Work Step by Step

We know $A^3=A\times A \times A=\{(a,b,c): a\in A, b\in A, \text{ and } c\in A\},$ and we can use this to do parts (a) and (b). a) For $A=\{a\}$, $A^3=\{(a,a,a)\}.$ b) For $A=\{0,a\}$, $A^3=\{(0,0,0), (0,0,a), (0,a,0), (0,a,a), (a,0,0), (a,0,a), (a,a,0), (a,a,a)\}.$
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