Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 1 - Section 1.8 - Proof Methods and Strategy - Exercises - Page 108: 9

Answer

Yes. Consider the integers from 2501 to 2600. This proof is constructive.

Work Step by Step

$50^2$ is $2500$ and $51^2$ is $2601$. There can't be any perfect squares between these two because $n^2$ is monotonic for positive $n$ and as such any square between these would have to be the square of a non-integer.
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