Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 1 - Section 1.7 - Introduction to Proofs - Exercises - Page 91: 2

Answer

Here is the proof to this staement. We are to prove that sum of two even integers is even.

Work Step by Step

SOLUTION: Let, First even integer (a) = 2k Secon d even integer (b) = 2a where, k & a are both any integers. Now, a + b = even i.e. multiple of 2 So, a + b = 2k + 2a 2(k+a) = even. REASON: As, k & a are integers and (k+ a) is multiple of 2. Hence, Proved.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.