Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 1 - Section 1.1 - Propositional Logic - Exercises - Page 16: 42

Answer

a) x=2 b) x=1 c) x=2 d) x=1 e) x=2

Work Step by Step

x=1. Here, we want to see whether this value of x satisfies the condition specified; if so, we perform the second operation to find the new value for x. Otherwise, x remains unchanged. a) x+2=3, so x=1+1=2 b) neither x+1=3 or 2x+2=3, so x=1 c) 2x+3=5 and 3x+4=7, so x=1+1=2 d) both x+1=2 and x+2=3, so by the XOR function this statement is false and x=1 e) x<2, so x=1+1=2
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